2x/((4x^2)-8x+4)

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Solution for 2x/((4x^2)-8x+4) equation: 


D( x )

4*x^2-(8*x)+4 = 0

4*x^2-(8*x)+4 = 0

4*x^2-(8*x)+4 = 0

4*x^2-8*x+4 = 0

4*x^2-8*x+4 = 0

DELTA = (-8)^2-(4*4*4)

DELTA = 0

x = 8/(2*4)

x = 1 or x = 1

x in (-oo:1) U (1:+oo)

(2*x)/(4*x^2-(8*x)+4) = 0

(2*x)/(4*x^2-8*x+4) = 0

4*x^2-8*x+4 = 0

4*(x^2-2*x+1) = 0

x^2-2*x+1 = 0

DELTA = (-2)^2-(1*1*4)

DELTA = 0

x = 2/(1*2)

x = 1 or x = 1

4*(x-1)^2 = 0

(2*x)/(4*(x-1)^2) = 0

2*x = 0 // : 2

x = 0

x = 0

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